import matplotlib.pyplot as plt
import numpy as np
import pandas as pd
import seaborn as sns
import matplotlib.pyplot as plt
import utils
from load_dataset import load_dataset, feature_extraction

pd.set_eng_float_format(accuracy=2, use_eng_prefix=True)

data_directory = "/Users/nepal/Documents/synapthesis/synData6July"
lotti_fn = "export_lotti_veneto_2016_2018_giulio_v2.csv"
vincitori_fn = "export_vincitori_veneto_2016_2018_giulio_v2.csv"
procedura_fn = "tipi_procedure.csv"

df = load_dataset(data_directory, lotti_fn, vincitori_fn, procedura_fn)
df = feature_extraction(df)
df.dtypes

importo values to substitute with importo_base_asta values percentage:           0.0012%
data_inizio values to substitute with data_inferita values percentage:           0.3145%
columns dropped with mostly missing values:
['oggetto', 'importo_liquidato', 'importo_base_asta', 'data_inferita', 'id_mod_realizz', 'cpv_vero']
dropped all the rows with at least one missing value

id_pa                                int64
id_scelta_contraente                 int64
importo                            float64
data_inizio                 datetime64[ns]
data_fine                   datetime64[ns]
id_lsf                               int64
id_forma_giuridica_pa                int64
uber_forma_giuridica_pa             object
cpv                                  int64
id_be                                int64
id_forma_giuridica_be                int64
uber_forma_giuridica_be             object
procedura                           object
tipo_procedura                      object
median_expenditure_pa              float64
median_revenue_be                  float64
contr_med_pa                       float64
contr_med_be                       float64
durata                     timedelta64[ns]
day_of_year_sin                    float64
day_of_year_cos                    float64
med_yearly_n_contr_pa              float64
med_yearly_n_contr_be              float64
dtype: object

anni e luogo dei contratti

abc analysis for award procedures and cpv codes

fig, ax = plt.subplots()
abc_scelta_contraente = utils.plot_abc_items(df, "id_scelta_contraente", ax, .9)

category within 0.9 - ROW COUNT
id_scelta_contraente
1       6022
26     25998
4      32604
23    588116
dtype: int64

scelta_contraente_mask = df.id_scelta_contraente == abc_scelta_contraente[0] for item in abc_scelta_contraente: scelta_contraente_mask += df.id_scelta_contraente == item df = df[scelta_contraente_mask]

fig, ax = plt.subplots(figsize=(6*2, 4))
abc_cpv = utils.plot_abc_items(df, "cpv", ax, .64)

category within 0.64 - ROW COUNT
cpv
33    88586
45    32560
85     8514
79    17620
55    14015
dtype: int64

cpv_mask = df.cpv == abc_cpv[0] for item in abc_cpv: cpv_mask += df.cpv == item df = df[cpv_mask]

abc_procedures = [1, 26, 4, 23]
abc_cpv = [33, 45, 85, 79]

procedure_mask = df.id_scelta_contraente == abc_procedures[0]
for item in abc_procedures:
    procedure_mask += df.id_scelta_contraente == item
df = df[procedure_mask]

cpv_mask = df.cpv == abc_cpv[0]
for item in abc_cpv:
    cpv_mask += df.cpv == item
df = df[cpv_mask]

scatterplots

is the contract duration linearly dependent on the contract amount?

for cpv in abc_cpv:
    utils.scatter_quaternion("durata", "importo", df, cpv)

the bigger the contract amount, the bigger the business entity?

for cpv in abc_cpv:
    utils.scatter_quaternion("median_revenue_be", "importo", df, cpv)

the bigger the contract amount, the bigger the PA median annual expenditure?

for cpv in abc_cpv:
    utils.scatter_quaternion("importo", "median_expenditure_pa", df, cpv)

do big PAs buy from big business entities?

for cpv in abc_cpv:
    utils.scatter_quaternion("median_revenue_be", "median_expenditure_pa", df, cpv)

time series

import matplotlib.colors as mcolors
n = len(abc_procedures)
fig, ax = plt.subplots(n, figsize=(6*3, 4.5*n))
for i, (name, group) in enumerate(df.groupby("tipo_procedura")):
    aggr = group.groupby("data_inizio").size()
    ax[i].plot(aggr / aggr.sum() , label=name, c=list(mcolors.TABLEAU_COLORS)[i])
    ax[i].legend()
    i += 1
plt.show()

outlier classification and filtering

• near-illegal outliers. The contracts are not compliant to the at-that-time public procurement law. This is a first approximation as waivers and exceptions are possibile.
• unsound/unreasable outliers. The contract values are very unrealistic given the other contract dimensions, such as the dimension of the firm or the duration
• statistical outliers. The contracts outlined by the evaluation of a statistical model applied to the dataset filtered of the previous outlier categories

near-illegal outliers

according to https://www.bosettiegatti.eu/public/2019_memo_pubblicita.pdf

# append a new col to keep track of the changes
df["noncompliant"] = False

the only award procedures present in the dataset:

• 1 : "procedura aperta",
• 4 : "procedura ristretta",
• 23 : "affidamento diretto"

works

• affidamento diretto: contract value < 150k
• procedura negoziata: 150k <= contract value < 1M
• procedura aperta: 1M <= contract value < 5.35M
• procedura aperta o ristretta: 5.35M >= contract value

quindi non posso avere procedure ristrette sotto i 5.35M? è la somma dei lotti o la gara che deve rispettare tali soglie?

# cpv does not match the lsf classification
sum(df.id_lsf == 1) - sum((df.id_lsf == 1) & (df.cpv == 45))

618

Let's forget about them. We will eventually keep them in consideration

df.loc[(df.id_lsf == 1) & (df.id_scelta_contraente == 23) & (df.importo < 150e3), "noncompliant"] = False

goods and services

• affidamento diretto: contract value < 40k
• procedura negoziata: 140k <= contract value < 214k
• procedura aperta o ristretta: 214k >= contract value

df.loc[(df.id_lsf != 1) & (df.id_scelta_contraente == 23) & (df.importo < 40e3), "noncompliant"] = False

sum(df.noncompliant)

unsound/unreasonable outliers

1. contracts having a value higher than the median annual revenue of the business entity winning the bid and of the median expenditure of the public commissioning body (stazione appaltante). Both the business entity and the commissioning body must have a median annual number of contracts higher or equal than five.

df["unsound"] = False

min_year_contr_th = 5
rev_exp_mask = (df.importo > df.median_revenue_be) & (df.importo > df.median_expenditure_pa)
min_year_contr_mask = (df.med_yearly_n_contr_be > min_year_contr_th) & (df.med_yearly_n_contr_pa > min_year_contr_th)
df.loc[rev_exp_mask & min_year_contr_mask, "unsound"] = True

relevant_attributes = ["importo", "cpv", "durata", 
                       "median_revenue_be", "med_yearly_n_contr_be", 
                       "median_expenditure_pa", "med_yearly_n_contr_pa"]
df[df.unsound][relevant_attributes]

	importo	cpv	durata	median_revenue_be	med_yearly_n_contr_be	median_expenditure_pa	med_yearly_n_contr_pa
147144	3.40M	45	489 days	2.69M	7.00	2.52M	142.00
301546	604.50k	33	1052 days	225.69k	8.00	579.61k	29.00
312636	117.78M	33	1003 days	14.21M	361.00	2.39M	16.00
315028	6.28M	45	734 days	3.00M	6.00	6.12M	248.00
354667	2.89M	45	476 days	408.13k	17.00	1.28M	271.00
356630	274.05k	45	180 days	148.79k	28.00	138.59k	78.00
356631	274.05k	45	180 days	265.59k	13.00	138.59k	78.00
391428	608.00k	45	1460 days	142.25k	6.00	454.50k	69.00
407688	4.93M	85	1095 days	4.71M	8.00	2.67M	12.00
429764	6.53M	85	1095 days	53.10k	11.00	793.01k	100.00
452416	4.41M	45	642 days	3.09M	21.00	684.57k	109.00
675287	5.80M	33	1256 days	5.74M	36.00	3.90M	137.00
681356	1.58M	45	781 days	843.53k	13.00	584.98k	78.00
695820	2.00M	33	1521 days	180.13k	15.00	1.70M	65.50
704876	205.54M	45	147 days	1.45M	11.00	1.05M	86.00
705278	1.45M	45	550 days	398.32k	20.00	453.03k	10.00
705279	1.45M	45	550 days	2.79k	6.00	453.03k	10.00
705280	1.45M	45	550 days	236.71k	7.00	453.03k	10.00
716184	10.11M	85	2191 days	8.22M	7.00	1.99M	198.00

1. affidamenti diretti having contract duration lasting longer than 10 years

n_years = 10
years_mask = (df.id_scelta_contraente == 23) & (df.durata.dt.days > n_years * 365)
sum(years_mask)
df.loc[years_mask, "unsound"] = True
df[years_mask][relevant_attributes]

	importo	cpv	durata	median_revenue_be	med_yearly_n_contr_be	median_expenditure_pa	med_yearly_n_contr_pa
45264	49.00k	45	4383 days	49.61k	2.00	6.33M	104.00
371881	38.00k	79	3847 days	38.00k	1.00	5.75M	366.00
445990	6.70k	79	4016 days	5.34k	1.50	2.39M	99.00
446018	5.38k	79	4016 days	5.38k	1.00	2.39M	99.00
446019	5.38k	79	4016 days	67.41k	11.00	2.39M	99.00
446146	12.27k	79	4016 days	27.30k	7.00	2.39M	99.00
446560	3.54k	79	4016 days	3.54k	1.00	2.39M	99.00
446590	1.74k	79	3919 days	5.34k	1.50	2.39M	99.00
446591	409.84	79	3784 days	28.84k	3.00	2.39M	99.00
446593	4.78k	79	4002 days	93.37k	10.00	2.39M	99.00
446594	2.14k	79	3653 days	1.65k	1.00	2.39M	99.00
446596	1.14k	79	3950 days	1.65k	1.00	2.39M	99.00
591345	15.00k	79	3652 days	15.00k	1.00	1.33M	150.00
699146	49.83k	79	3651 days	10.30k	4.00	3.09M	4.00
711869	7.50k	85	4659 days	2.54k	3.00	5.98M	254.00

1. contracts having a value 25 times higher than the median revenue of business entity and more than 5 contracts (median)

coef = 25
coef_mask = (df.importo > coef * df.median_revenue_be) & (df.med_yearly_n_contr_be > 5)
df.loc[coef_mask, "unsound"] = True
df.loc[coef_mask, relevant_attributes]

	importo	cpv	durata	median_revenue_be	med_yearly_n_contr_be	median_expenditure_pa	med_yearly_n_contr_pa
31713	4.46M	33	2009 days	62.47k	6.00	101.71M	2.46k
60826	1.40M	79	1786 days	52.24k	11.00	84.30M	657.00
89682	27.24M	45	1094 days	805.64k	10.00	27.24M	5.00
99458	470.35k	85	1095 days	13.04k	30.00	11.86M	303.00
104224	18.27M	85	291 days	29.08k	6.00	481.50M	37.00
170757	52.92M	33	771 days	1.27M	29.00	189.71M	2.05k
208558	15.00M	33	821 days	94.87k	6.00	49.45M	668.00
317284	5.75M	33	688 days	113.39k	11.00	189.71M	2.05k
319872	30.00M	45	679 days	245.27k	7.00	86.51M	344.00
333305	1.21M	33	365 days	30.23k	11.00	228.08M	2.94k
349964	1.23M	45	268 days	8.37k	18.00	4.55M	353.00
376930	406.68k	45	365 days	6.66k	36.00	1.82M	26.00
429764	6.53M	85	1095 days	53.10k	11.00	793.01k	100.00
445754	320.00k	45	242 days	4.69k	8.00	3.08M	99.00
479905	1.51M	33	824 days	51.94k	6.00	228.08M	2.94k
490566	15.69M	33	688 days	624.78k	82.00	189.71M	2.05k
491372	3.99M	33	729 days	107.30k	14.00	354.66M	1.47k
518961	960.00k	79	1074 days	25.61k	7.00	38.85M	892.00
570522	285.25k	79	537 days	5.80k	34.00	57.08M	191.00
604136	10.00M	33	821 days	94.87k	6.00	49.45M	668.00
688688	356.78k	85	1095 days	13.04k	30.00	11.86M	303.00
704876	205.54M	45	147 days	1.45M	11.00	1.05M	86.00
705279	1.45M	45	550 days	2.79k	6.00	453.03k	10.00
751297	4.60M	45	776 days	164.04k	10.00	13.80M	3.00
755107	20.61M	85	183 days	679.18k	10.00	241.96M	260.00

utils.compare_filtering(df, "importo", "median_revenue_be", "noncompliant")

utils.compare_filtering(df, "importo", "median_revenue_be", "unsound", alpha=1)

• vedere importo e periodo dell'anno dati procedure e cpv
• chiamare Claudio per domande sulle regole ex codice appalti, mostrare a Claudio i grafici.
• modello